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two years ago a man was six times as old as his daughter. In 18 years he will be twice as old as her, determine their present ages

Respuesta :

lacampanella

Step-by-step explanation:

Let m = man's age right now

d = daughter's age right now

m-2 = 6(d-2)  =>  m = 6d -12 +2 = 6d-10

m+18 = 2(d+18)   =>   m = 2d+36-18 = 2d+18

6d-10 = 2d+18

4d = 28

d = 7

m = 32

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