Answer:
[tex]\frac{25}{36}[/tex]
Step-by-step explanation:
Since each dice has a total of 6 numbers, Peter can get a maximum roll of 5 on each dice before the total is 11 or more. Therefore, the probability of rolling a number less than or equal to 5 each roll is 5/6. Now to find the probability of rolling a 5 or less in both rolls together so that the total is less than 11 we need to multiply the probability of each separate roll together.
[tex]\frac{5}{6} * \frac{5}{6} = \frac{25}{36}[/tex]
Therefore the probability of the total being less than 11 is [tex]\frac{25}{36}[/tex]
