Answer:
The side length of the prints is approximately 34.785 inches.
Step-by-step explanation:
First, we have to calculate the area of the original oil painting ([tex]A[/tex]), measured in square inches, by the following formula:
[tex]A = l^{2}[/tex] (1)
Where [tex]l[/tex] is the length of the side, measured in inches.
And the length of the miniature is determine by means of reduction factor ([tex]k[/tex]), with no unit:
[tex]\frac{A}{k} = l'^{2}[/tex] (2)
If we know that [tex]l = 55\,in[/tex] and [tex]k = 2.5[/tex], then the side length of the miniatures is:
[tex]l' = \sqrt{\frac{l^{2}}{k} }[/tex]
[tex]l' = \frac{l}{\sqrt{k}}[/tex]
[tex]l' = \frac{55\,in}{\sqrt{2.5}}[/tex]
[tex]l' \approx 34.785\,in[/tex]
The side length of the prints is approximately 34.785 inches.
