Answer:
[tex]m_{O_2}=36.3gO_2[/tex]
Explanation:
Hello!
In this case, since the reaction between propane and oxygen is:
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
Given the 1:5 mole ratio between propane and oxygen, and their molar masses (44.09 g/mol and 32.00 g/mol respectively), we can follow up the shown below stoichiometric setup to compute the required mass of oxygen for the reaction:
[tex]m_{O_2}=10.0gC_3H_8*\frac{1molC_3H_8}{44.09gC_3H_8}*\frac{5molO_2}{1molC_3H_8} *\frac{32.00gO_2}{1molO_2} \\\\m_{O_2}=36.3gO_2[/tex]
Best regards!
