Answer:
[tex]m_{Li_3N}=9.06gLi_3N[/tex]
Explanation:
Hello!
In this case, since the reaction between nitrogen and lithium to obtain lithium nitride is:
[tex]6Li+N_2\rightarrow 2Li_3N[/tex]
Starting by that amount of atoms of lithium, we first need to compute the moles of lithium via the Avogadro's number:
[tex]n_{Li}=4.7x10^{23}atoms*\frac{1molLi}{6.022x10^{23}atoms}=0.78molLi[/tex]
Now, by using the 6:2 mole ratio between lithium and lithium nitride and the molar mass of this product (34.83 g/mol), we can compute the required grams as shown below:
[tex]m_{Li_3N}=0.78molLi*\frac{2molLi_3N}{6molLi}*\frac{34.83gLi_3N}{1molLi_3N} \\\\m_{Li_3N}=9.06gLi_3N[/tex]
Best regards!
