What is the magnitude of the centripetal

force that must be applied in order for a

0.5 kg ball on a 2.0 m string to spin with

uniform circular motion at 5.0 m/s?

Respuesta :

Answer:

Explanation:

6.25

Ver imagen andreslaverdez333

The magnitude of the centripetal force that must be applied is 6.25 N.

The given parameters;

  • mass of the object, m = 0.5 kg
  • velocity of the object, v = 5 m/s
  • radius of the string, r = 2 m

The magnitude of the centripetal force that must be applied is determined by the product of the mass of the object and the centripetal acceleration.

The centripetal force is calculated as follows;

[tex]F_c = ma_c = \frac{mv^2}{r} \\\\F_c = \frac{0.5 \times 5^2}{2} \\\\F_c = 6.25 \ N[/tex]

Thus, the magnitude of the centripetal force that must be applied is 6.25 N.

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