A publisher reports that 52% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 180 found that 46% of the readers owned a laptop. Find the value of the test statistic. Round your answer to two decimal places.

Respuesta :

Answer:

The value of the test statistic is [tex]t = -1.61[/tex]

Step-by-step explanation:

Central Limit Theorem

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Our test statistic is:

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the expected mean, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

A publisher reports that 52% of their readers own a laptop.

This means that [tex]\mu = 0.52[/tex]

Sample of 180:

Means that [tex]n = 180[/tex]

By the Central Limit Theorem:

[tex]\frac{\sigma}{\sqrt{n}} = s = \sqrt{\frac{0.52*0.48}{180}} = 0.0372[/tex]

A random sample of 180 found that 46% of the readers owned a laptop.

This means that [tex]X = 0.46[/tex]

Find the value of the test statistic.

[tex]t = \frac{X - \mu}{s}[/tex]

[tex]t = \frac{0.46 - 0.52}{0.0372}[/tex]

[tex]t = -1.61[/tex]

The value of the test statistic is [tex]t = -1.61[/tex]