Answer:
1.66
Step-by-step explanation:
We need to conduct a chi square test
The statistic used to check this is given by the below
∑(n, 1) = [(O(i) - E(i)] / E(i)
From the question, we're told the observed value is
Freshmen
Sophomore
Junior
Senior.
After that, we then calculate the expected value.
Freshman
0.3 * 300 = $90
Sophomore
0.24 * 300 = $72
Statistics then finally gives us this
X² = (93 - 90²)/90 + (68 - 72)²/72 + (85 - 78)/78 + (64 -60)²/60
X² = 3² / 90 + 4² / 73 + 13² / 78 + 4² / 60
X² = 0.1 + 0.212 + 2.167 + 0.266 x+
X² = 2.745
X = √2.745
X = 1.66
