On a coordinate plane, the center of dilation is at (0, 0). Triangle A B C has points (negative 4, 3), (4, 4), and (1, 1).
A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the image △A'B'C'? Check all that apply.

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Answer:

Explanation:

Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).

As, DO is Dilation of Δ ABC by Scale factor of .

Vertices of A' B'C' are

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.

The two triangles will be congruent.

AO is Dilated by a factor of half , so A'O' will be half of AO.

So, correct Statements are

1. AB is parallel to A'B'.

2.DO,1/2(x, y) =  

The distance from A' to the origin is half the distance from A to the origin.

AB is parallel to A'B' , DO,1/2(x, y) = (one-half x, one-half y), and    the distance from A' to the origin is half, the distance from A to the origin. Correct Statements are   A, B, and C.

Given here,

Coordinates of Vertices of triangle ABC,

A = (-4,3) , B = (4,4) and C = (1,1).  

DO is the Dilation of Δ ABC by Scale factor of half.    

Hence, Image Δ A'B'C' is smaller than the Pre-image Δ ABC.  

The two triangles will be congruent.  

if AO is Dilated by a factor of half , so A'O' will be half of AO.  

Therefore, correct Statements are   AB is parallel to A'B' , DO,1/2(x, y) = (one-half x, one-half y), and    the distance from A' to the origin is half, the distance from A to the origin.

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