The velocity of an object in meters per second varies directly with time in seconds since the object was dropped, as represented by the table.

A two column table with 6 rows. The first column has, Time in seconds, and has the entries, 0, 1, 2, 3, 4. The second column, Velocity in meters per second, has the entries, 0, 9.8, 19.6, 29.4, 39.2.
The acceleration due to gravity is the constant of variation. What is the acceleration due to gravity of a falling object?

4.9 9.8 StartFraction m Over s squared EndFraction.
9.8 9.8 StartFraction m Over s squared EndFraction.
10.2 10.2 StartFraction m Over s squared EndFraction.
19.6 19.6 StartFraction m Over s squared EndFraction.

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Answer:

B

Step-by-step explanation:

edg2021

The value of the acceleration due to gravity is 9.8 m/s^2.

What is the acceleration due to gravity?

Now we know that the acceleration due to gravity is the slope when you plot the graph of velocity against time for motion under gravity.

Now we must look at the data given and use;

v = u + at

Given that the object was dropped, u = 0 hence

v = at

at t = 1 s and v = 9.8 m/s

a = 9.8 m/s/ 1 s

a = 9.8 m/s^2

This value remains the same irrespective of the time that you pick hence it is the value of the acceleration due to gravity.

Learn more about acceleration due to gravity:https://brainly.com/question/10892047

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