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The equation [tex]x^3-x^2+ax+b=0[/tex] has three integer solutions.

Two of these solutions are [tex]x=1[/tex] and [tex]x=2[/tex].

Work out the third solution to the equation.

Respuesta :

Answer:

x = - 2

Step-by-step explanation:

x³-x²+ax+b = (x-1)(x-2)(x+c) = x³ + (c-3)x² + (2-3c)x +2c

c-3 = -1       C = 2

a = 2 - 3c = 2 - 3*2 = - 4

b = 2c = 4

third solution: x+2=0    x=-2

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