contestada

1. Deshaun Watson (100 kg) accelerates from rest to 9.0 m/s in 1.5 s. What is the average power
output of Deshaun in kW? (2 mark)

Respuesta :

Answer:

P = 5400[W]

Explanation:

We must use the following equation of kinematics to calculate the acceleration.

[tex]v_{f}=v_{o}+a*t[/tex]

where:

Vf = final velocity = 9 [m/s]

Vo = initial velocity = 0 (starting from rest)

a = acceleration [m/s²]

t = time = 1.5 [s]

[tex]9=0+a*1.5\\a=9/1.5\\a=6[m/s^{2} ][/tex]

Now with this second equation of kinematics, we can determine the distance traveled.

[tex]v_{f}^{2}=v_{o}^{2}+2*a*x[/tex]

where:

x= distance [m]

[tex]9^{2} = 0 +2*6*x\\12*x=81\\x=6.75[m][/tex]

Now we must use Newton's second law which tells us that the sum of forces is equal to the product of mass by acceleration.

∑F = m*a

Now replacing:

[tex]F=100*6\\F=600[N][/tex]

Ahora la potencia se puede calcular por medio del producto de la fuerza por velocidad.

[tex]P=F*v[/tex]

where:

P = power [W]

F = force = 600 [N]

v = velocity = 9 [m/s]

[tex]P=9*600\\P=5400[W][/tex]