Step-by-step explanation:
[tex]v = {x}^{3} \\ {v}^{2} + 3v - 5 = 0 \\ [/tex]
Solving this equation using the quadratic formula, we get two real solutions :
1.1926 or -4.1926
Now we know the values of v , we can calculate x since x is ∛ v
[tex] {x}^{6} + 3 {x}^{3} - 5 = 0[/tex]
[tex]x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125[/tex]
