The area of the triangle ABC is 34.2 square centimeters
The complete question is in the image
Start by calculating the semi-perimeter using:
s = 0.5 * (a + b + c)
This gives
s = 0.5 * (9 + 10 + 8)
Evaluate
s = 13.5
The area is then calculated as:
[tex]A = \sqrt{s * (s - a) * (s - b) * (s - c)[/tex]
This gives
[tex]A = \sqrt{13.5 * (13.5 - 9) * (13.5 - 10) * (13.5 - 8)[/tex]
Evaluate
A = 34.2
Hence, the area of the triangle ABC is 34.2 square centimeters
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