Respuesta :

Answer:

16.1 s

Explanation:

The reaction,  A → Products, follows first order kinetics.

So,

ln[A] = ln[A]o - kt

Where;

[A] = concentration at time= t

[A]o = initial concentration

k= rate constant

t = time taken

ln(0.205) = ln(0.850) - 0.0882t

ln(0.205) -  ln(0.850) = - 0.0882t

-1.5847 - (-0.1625) = - 0.0882t

-1.5847 + 0.1625 = - 0.0882t

-1.4222 = - 0.0882t

t = -1.4222/- 0.0882

t = 16.1 s

Based on first order kinetics, the time taken for the concentration of A to decrease from 0.850 M to 0.205 M is 16.1 seconds.

What is order of a reaction?

The order of a reaction refers to the relationship between the rate of a reaction and the the concentration of each reactant.

For a first-order reaction, the rate is dependent on the concentration of a single species.

The reaction,  A → Products is a first order reaction.

Therefore, using the first order kinetics equation

ln[A] = ln[A]° - kt

Where;

  • [A] = concentration at time= t
  • [A]° = initial concentration
  • k= rate constant
  • t = time taken

Substituting the values:

ln(0.205) = ln(0.850) - 0.0882t

ln(0.205) -  ln(0.850) = - 0.0882t

-1.5847 - (-0.1625) = - 0.0882t

-1.5847 + 0.1625 = - 0.0882t

-1.4222 = - 0.0882t

t = -1.4222/- 0.0882

t = 16.1 s

Therefore, the time taken for the concentration of A to decrease from 0.850 M to 0.205 M is 16.1 seconds.

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