Answer: The new temperature of the water bath is [tex]31.9^0C[/tex]
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat released by water =[tex]69.0kJ=69000J[/tex] (1kJ=1000J)
m= mass of water = 8.10 kg= 8100 g (1kg=1000g)
c = specific heat capacity = [tex]4.184J/g^0C[/tex]
Initial temperature of the water = [tex]T_i[/tex] = [tex]33.9^0C[/tex]
Final temperature of the water = [tex]T_f[/tex] = ?
Change in temperature ,[tex]\Delta T=T_f-T_i[/tex]
Putting in the values, we get:
[tex]-69000J=8100g\times 4.184J/g^0C\times (T_f-33.9)^0C[/tex]
[tex]T_f=31.9^0C[/tex]
The new temperature of the water bath is [tex]31.9^0C[/tex]
