Answer:
hello your question is incomplete attached below is the complete question
answer :
for I1 = [tex]\frac{1}{x^2} + \frac{4}{x^3}[/tex] The integral converges
for I2 = [tex]\frac{2x + 6}{2(x^2 + 6x + 4 )}[/tex] The integral diverges
for I3 = [tex]\frac{1}{x^2}[/tex] The integral converges
for I4 = 1 The integral diverges
Step-by-step explanation:
The similar integrands and the prediction ( conclusion )
for I1 = [tex]\frac{1}{x^2} + \frac{4}{x^3}[/tex] The integral converges
for I2 = [tex]\frac{2x + 6}{2(x^2 + 6x + 4 )}[/tex] The integral diverges
for I3 = [tex]\frac{1}{x^2}[/tex] The integral converges
for I4 = 1 The integral diverges
attached below is a detailed solution