Answer:
Step-by-step explanation:Given : right triangle ABC , AE^2 + EB^2 =9 and BE^2 + EC^2 = 16
To find : AC
Solution:
BE ⊥ AC
∠AEB = 90°
=> ΔAEB is right angled
=> AB² = AE² + EB²
=> AB² = 9
∠BEC = 90°
=> ΔBEC is right angled
=> BC² = BE² + EC²
=> BC² = 16
∠ABC = 90°
=> AC² = AB² + BC²
=> AC² = 9 + 16
=> AC² = 25
=> AC = 5
AC = 5
