together dien and jane eat 2/3 a pizza in 4 seconds. how long would it take each of them to eat the whole pizza alone if jane can eat a pizza 5 seconds faster than dien?

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Answer:

10 secs for Jane and Dien is 15 secs

Step-by-step explanation:

Using the together rate, it is found that Jane can eat a pizza in 10 seconds and Dien in 15 seconds.

What is the together rate?

It is the sum of each separate rate.

In this problem, the rates are:

  • Dien's rate: 1/x+5.
  • Jane's rate: 1/x.
  • Together rate: (2/3)/4 = 1/6

Hence:

[tex]\frac{1}{x + 5} + \frac{1}{x} = \frac{1}{6}[/tex]

[tex]\frac{x + x + 5}{x(x+5)} = \frac{1}{6}[/tex]

[tex]\frac{2x + 5}{x^2 + 5x} = \frac{1}{6}[/tex]

[tex]x^2 - 7x - 30 = 0[/tex]

[tex](x - 10)(x + 3) = 0[/tex]

The positive solution is x = 10, hence Jane can eat a pizza in 10 seconds and Dien in 15 seconds.

More can be learned about the together rate at https://brainly.com/question/25159431