Answer:
The perimeter of the garden, in meters, is [tex]24\sqrt{2}[/tex]
Step-by-step explanation:
Diagonal of a square:
The diagonal of a square is found applying the Pythagorean Theorem.
The diagonal of the square is the hypothenuse, while we have two sides.
Diagonal of 12m:
This means that [tex]d = 12[/tex], side s. So
[tex]s^2 + s^2 = 12^2[/tex]
[tex]2s^2 = 144[/tex]
[tex]s^2 = \frac{144}{2}[/tex]
[tex]s^2 = 72[/tex]
[tex]s = \sqrt{72}[/tex]
Factoring 72:
Factoring 72 into prime factors, we have that:
72|2
36|2
18|2
9|3
3|3
1
So
[tex]72 = 2^{3}*3^{2}[/tex]
So, in simplest radical form:
[tex]s = \sqrt{72} = \sqrt{2^{3}*3^{2}} = \sqrt{2^3}*\sqrt{3^2} = 2\sqrt{2}*3 = 6\sqrt{2}[/tex]
Perimeter of the garden:
The perimeter of a square with side of s units is given by:
[tex]P = 4s[/tex]
In this question, since [tex]s = 6\sqrt{2}[/tex]
[tex]P = 4s = 4*6\sqrt{2} = 24\sqrt{2}[/tex]
The perimeter of the garden, in meters, is [tex]24\sqrt{2}[/tex]
