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anyone please write an easy solution to solve this linear equation with brackets:

16-4(x+3)=2x

anyone pls explain i keep getting 7/2!!

Respuesta :

VectorFundament120

Answer:

[tex] \large \boxed{x = \frac{2}{3} }[/tex]

Step-by-step explanation:

Goal

  • Solve the equation for x-term.

Given

  • Equation

[tex] \large{16 - 4(x + 3) = 2x}[/tex]

Step 1

  • Distribute/Expand 4 in the expression.

[tex]16 - 4x - 12 = 2x[/tex]

Step 2

  • Isolate x and combine like terms.

[tex]16 - 12 = 2x + 4x[/tex]

Step 3

  • Solve the equation for x-term

[tex]4 = 6x \\ \frac{4}{6} = x \\ \frac{2}{3} = x[/tex]

Step 4

  • If you are not sure that the answer is correct, I suggest to check the answer by substituting the value of x in the equation.

[tex]16 - 4x - 12 = 2x[/tex]

Substitute x = 2/3 in the equation.

[tex]16 - 4( \frac{2}{3} ) - 12 = 2 (\frac{2}{3} ) \\ 4 -4( \frac{2}{3} ) = 2( \frac{2}{3} )[/tex]

Evaluate

[tex]4 - \frac{8}{3} = \frac{4}{3} [/tex]

Move -8/3 to add with 4/3.

[tex]4 = \frac{4}{3} + \frac{8}{3} \\ 4 = \frac{12}{3} \\ 4 = 4[/tex]

The equation is true for x = 2/3. Hence, the solution is x = 2/3.

Hope this helps! Any questions about the answer can be asked in comments.

~ Vectør ~

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