Please help!! I will make you brainlest.

The first triangle is a 45 45 90 degree triangle (I'm talking about the angles), and so, the ratio is 1:1:[tex]\sqrt{2\\}[/tex], so I have to divide the hypotenuse by [tex]\sqrt{2\\}[/tex] to get the legs. The hypotenuse is 15[tex]\sqrt{6}[/tex], so that divided by [tex]\sqrt{2\\}[/tex] is 15[tex]\sqrt{3\\}[/tex]. X is the same length as y because of the triangle ratio, so both x and y for the first triangle are 15[tex]\sqrt{3\\}[/tex].

The second triangle is a 30 60 90 degree triangle, so the ratio is x:x[tex]\sqrt{3}[/tex]:2x. The short leg is 7[tex]\sqrt{3}[/tex], so 7[tex]\sqrt{3}[/tex] * 2 is the hypotenuse, which is 14[tex]\sqrt{3}[/tex]. The long leg is 7[tex]\sqrt{3}[/tex] * [tex]\sqrt{3}[/tex], which is 21. So, x for the second triangle is 14[tex]\sqrt{3}[/tex], and y for the second triangle is 21.

SValore SValore · Answer 2 · 2021-02-23T19:36:33+01:00

Answer:

Question 9: x = [tex]15\sqrt{3}[/tex], Question 10: y = [tex]15\sqrt{3}[/tex], Question 11: x = [tex]14\sqrt{3}[/tex], Question 12: y = 21

Step-by-step explanation:

Question 9-10: Right triangles with 45°, 45°, 90° have a special rule, the legs of the triangle are equal, so x = y. Now you can form the statement [tex]2x^2 = 1350[/tex], and because x = [tex]15\sqrt{3}[/tex], so does y.

Question 11-12: Right triangles with 30°, 60°, 90° also have a special rule, the side corresponding to 30° is half the length of the hypotenuse and the side corresponding to 60° is [tex]\sqrt{3}[/tex] times as great as the 60°. x is 2 times as big as [tex]7\sqrt{3}[/tex], so its length is [tex]14\sqrt{3}[/tex]. Y is [tex]\sqrt{3}[/tex] as great as [tex]7\sqrt{3}[/tex], so its length is 21.