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Answer:

  (c)  No, it is not a rectangle because the diagonals are not congruent

Step-by-step explanation:

The diagonals of a rectangle bisect each other and are the same length. The lengths of the diagonals of this figure are ...

  AC = √((8-0)² +(6-2)²) = √(64+16) = 4√5

  BD = √((5-3)² +(2-6)²) = √(4 +16) = 2√5

The diagonals are different lengths, so the parallelogram is not a rectangle. This is described correctly in choice C:

  No, it is not a rectangle because the diagonals are not congruent.

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The lengths are found using the distance formula:

  d = √((x2 -x1)² +(y2 -y1)²)

It's C, the diagonals are not congruent (they aren't equal) and with rectangles they always have to be.