The acceleration of the car down the 36° slope will be 5.76 m/s²
Recall :
- Force, F = mass × acceleration
- F = ma
The force which tends to roll the car down the hill :
- Fsinθ
- 12000 × sin(36) = 7053.42 N
Mass of the car :
12000 = m × 9.8
m = 12000 / 9.8
m = 1224.49 kg
The acceleration of the car down slope :
- a = F/m ; F = Force which tends to pull the car down
a = (7053.42) ÷ 1224.49
a = 5.76 m/s²
Therefore, the acceleration of the car is 5.76 m/s²
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