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What volume of water can be boiled by 3.0 kJ of energy? (Refer to table of
constants for water.)
A. 3.0 kJ x
1 mol
x 18.02 g/mol
1 mL
= 13 mL
1 g
4.186 kJ
B. 3.0 kJ x 1 mol
* 18.02 g/mol
6.03 kJ
1 mL
= 9.0 mL
1 g
C. 3.0 kJ x
1 mol
x 18.02 g/mol
(-285.83 kJ)
1 mL
1g
= 0.19 mL
1 mL
D. 3.0 kJ x
1 mol
40.65 kJ
* 18.02 g/mol
= 1.3 mL
SUBMIT

Respuesta :

haleypieper24

Answer: 3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL

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