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helllppp i have a test!!!!
A compound has a molar absorptivity of 40.9 cm ^ - 1 * M ^ - 1 at 293 nm. If a 1.00 cm cuvette is used, and the absorbance found to be 0.111, what is the concentration of the sample ?

Respuesta :

maacastrobr

Answer:

0.00271 M

Explanation:

To solve this problem we can use the formula:

  • A = ε * C * l

Where A is the absorbance, ε is the molar absorptivity, C is the molar concentration and l is the optical path length.

We input the data given by the problem:

  • 0.111 = 40.9 cm⁻¹M⁻¹ * C * 1.00 cm

And solve for C:

  • C = 0.00271 M

The study of chemicals is called chemistry.

The correct answer is 0.00271 M

To solve this problem the formula is used as follows:-

A = ε * C * l

The data is given as follows:-

  • A is the absorbance,
  • ε is the molar absorptivity,
  • C is the molar concentration
  • l is the optical path length.

 

[tex]0.111 = 40.9 * C * 1.00[/tex]

After solving the equation the value of C is as follows:-

[tex]C = 0.00271 M[/tex]

Hence, the correct answer is 0.00271.

For more information, refer to the link:-

https://brainly.com/question/14698383

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