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Find three consecutive integers such that that product of the first and third is one
less than 22 times the second integer.

Respuesta :

siddharthdubey

Answer:

n = the first

n + 1 = the 2nd

n + 2 = the 3rd

n(n + 2) - (n + 1) = 10(n + 2) + 1

n2 + 2n - n - 1 = 10n + 20 + 1

n2 - 9n - 22 = 0

(n - 11)(n + 2) = 0

If two factors = 0, at least one must = 0.

n - 11 = 0

n = 11

11,12,13

n + 2 = 0

n = -2

-2,-1,0

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