Answer:
the force between the two charges is 198.37 N
Explanation:
Given;
charge of the first particle, Q₁ = -3 x 10⁻⁵ C
charge of the second particle, Q₂ = 9.0 x 10⁻⁵ C
distance between the two charges, r = 0.35 m
The force between the two charges is calculated from Coulomb's law;
[tex]F = \frac{kQ_1Q_2}{r^2}[/tex]
where k is Coulomb's constant = 9 x 10⁹ Nm²/C²
[tex]F = \frac{(9\times 10^9)(3.0\times 10^{-5})(9\times10^{-5} )}{0.35^2} \\\\F = 198.37 \ N[/tex]
Therefore, the force between the two charges is 198.37 N
