Answer:
Explanation:
All you need to know is the atomic mass of platinum, and Avogadro's number.
2.00g Pt divided by atomic mass gives you the moles of platinum, and multiplying by avogadro's number (6.022 x 10^23) gives you the number of atoms.
Atomic mass of platinum can be found on any periodic table.
Hope this helped.
12.04 × 10²³ number of platinum atoms are present in 2 grams of platinum.
To calculate the no. of atoms in any substance, we have to multiply the no. of moles of that substance by the Avogadro's no.
Value of Avogadro's no. = 6.022 × 10²³
We can calculate the mole by using the below formula:
n = W / M, where,
n = no. of moles
W = given mass = 2.00g
M = molar mass or atomic mass = 195.09 g/mol
n = 2 / 195.08 = 0.0102 mol
Number of atoms in 2.00g of platinum = 2 × 6.022 × 10²³ = 12.04 × 10²³.
Hence, number of atoms that are present in 2.00g of platinum is 12.04 × 10²³.
To learn more about Avogadro's no., visit below link:
https://brainly.com/question/1581342
