Answer:
The weight of an object at the poles is more than the weight of the object at the equator
Explanation:
The shape of the Earth is an ellipsoid such that the distance from the North and South poles to the Earth's center, R₁, is less than the distance from the Equator to the center of the Earth, R₂
The weight of an object is given by the universal gravitational law as follows;
[tex]Weight = F_{gravity} =G\times \dfrac{M \cdot m}{R^{2}}[/tex]
Where;
[tex]F_{gravity}[/tex] = The force of gravity = The weight of an object
G = The universal gravitational constant
M = The mass of the Earth
m = The mass of the object
R = The radius of the Earth
Where R₁ < R₂, we have;
The weight at the Poles, W₁ = [tex]G\times \dfrac{M \cdot m}{R_1^{2}}[/tex]
The weight at the Equator, W₂ = [tex]G\times \dfrac{M \cdot m}{R_2^{2}}[/tex]
We have;
[tex]\left(G\times \dfrac{M \cdot m}{R_1^{2}} \right) > \left(G\times \dfrac{M \cdot m}{R_2^{2}} \right) \because R_1 < R_2[/tex]
Therefore, the weight of an object at the poles, W₁, is more than the weight of the object at the equator, W₂
