An unknown substance with a mass of 83 grams absorbs 1,108 J while undergoing a
temperature increase of 11 °C. What is the specific heat of the substance?

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An unknown substance with a mass of 83 grams absorbs 1108 J while undergoing a temperature increase of 11 C What is the specific heat of the substance Look at p class=

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Answer:

The specific heat of the substance is 1.21 [tex]\frac{J}{g*C}[/tex]

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c*m*ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q=1108 J
  • c= ?
  • m= 83 g
  • ΔT= 11 C

Replacing:

1108 J= c*83 g* 11 C

Solving:

[tex]c=\frac{1108 J}{83 g* 11 C}[/tex]

c= 1.21 [tex]\frac{J}{g*C}[/tex]

The specific heat of the substance is 1.21 [tex]\frac{J}{g*C}[/tex]