A butterfly is flying 8 3/4 feet above the ground. It descends at a steady rate to a spot 6 1/4 feet above the ground in 1 2/3 minutes. What is the butterfly’s change in elevation each minute?

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Answer:

Step-by-step explanation:

6¼ ft - 8¾ ft = -2½ ft

(-2½ ft)/(1⅔ min) = (5/2 ft)/(5/3 min)

= (5/2)/(5/3) ft/min

= (5/2 × 3/5 ft)/min

= 1.5 ft /min

The required change in elevation of butterfly is 1.5 ft\min.

Given that,

A butterfly is flying [tex]8\frac{3}{4}[/tex] feet above the ground.

It descends at a steady rate to a spot [tex]6 \frac{1}{4}[/tex] feet above the ground in [tex]1\dfrac{2}{3}[/tex] minutes.

We have to determine,

The butterfly’s change in elevation each minute.

According to the question,

Change in elevation = butterfly flying above ground - it descends at a steady rate to a spot above the ground ,

[tex]= 8\dfrac{3}{4} - 6\dfrac{1}{4}\\\\= \dfrac{35}{4} - \dfrac{25}{4}\\\\= \dfrac{10}{4}\\\\= \dfrac{5}{2}\\\\= 2.5 feet[/tex]

Then,

To find Change in elevation per minute,

[tex]= T = 1\dfrac{2}{3} = \dfrac{5}3}[/tex]

Therefore,

Change in elevation per minute,

[tex]= \dfrac{2.5}{\frac{5}{3}} = 2.5 \times \dfrac{3}{5} = 1.5 \ ft \ per\ minute[/tex]

Hence, The required change in elevation of butterfly is 1.5 ft\min.

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