Answer:
[tex]2 \sqrt{15} [/tex]
Step-by-step explanation:
1) rewrite 60 as it's prime factors.
[tex] \sqrt{2 \times 2 \times 3 \times } 5[/tex]
2) group the smae prime factors into pairs.
[tex] \sqrt{(2 \times 2)} \times 3 \times 5[/tex]
3) Rewrite each pair in exponent form.
[tex] \sqrt{ {2}^{2} \times 3 \times 5 } [/tex]
4) use this role:
[tex] \sqrt{ {x}^{2} } = x[/tex]
[tex]2 \sqrt{3 \times 5} [/tex]
5) Simplify.
[tex]4 \sqrt{15} [/tex]
So, therefor, the answer is option 1.
