Answer:
F = 1.19 x 10⁹ N
Explanation:
The electrostatic force between the charged particles is given by Colomb's Law as follows:
[tex]F = \frac{kq_{1}q_{2}}{r^{2}}[/tex]
where,
F = Electrostatic force = ?
k = Colomb's constant = 9 x 10⁹ N.m²/C²
q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C
r = distance between protons = 4.4 x 10⁻¹⁰ m
Therefore,
[tex]F = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(4.4\ x\ 10^{-10})^{2}} \\\\[/tex]
F = 1.19 x 10⁹ N
