Answer:
Follows are the solution to the given question:
Explanation:
In this question the missing file of the circuit is not be which is defined in attached file please find it.
In Option 1, this statement is true because the current is on [tex]R_3 \ and \ R_4[/tex], that is the same.
In option 2, this statement is false because [tex]Rcd=R_3+R_4[/tex] therefore it implies that Rcd is always larger then [tex]R_3[/tex].
In option 3, this statement is true because the voltage of [tex]R_1 \ and \ R_2[/tex] is always equal.
In option 4, this statement is true because [tex]Rab= \frac{1}{(\frac{1}{R1}+\frac{1}{R2})}=\frac{R1R2}{(R1+R2)}. \frac{R2}{(R1+R2)}[/tex]is always smaller then 1 therefore,[tex]R_1 \times (\frac{R2}{(R1+R2)})[/tex] is always equal to R1.
