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HELP MEEE PLEASE




Gilligan sees a ship coming close to the shore he's standing on. He wants to

determine the distance (SD) from the ship to the shore. He walks 130 ft along the

shore from point D to point C and marks that spot. Then he walks 23 ft further and

marks point B. He turns 90 and walks until his location (point A), point C, and point

S are collinear.

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Answer the following questions making sure to show all your work.

(a) Can Gilligan conclude that triangle ABC and triangle SDC are similar? Why or why

not?

(b) Suppose AB = 90 ft. What can Gilligan conclude about the distance of the ship

from the shore? Explain.

HELP MEEE PLEASE Gilligan sees a ship coming close to the shore hes standing on He wants todetermine the distance SD from the ship to the shore He walks 130 ft class=

Respuesta :

MrRoyal

The triangles ABC and SDC are similar triangles

  • Gilligan can conclude that triangles ABC and SDC are similar
  • Gilligan can conclude that the distance of the ship from the shore is 509 ft

How to determine if the triangles are similar

From the question, we understand points S, C and A are collinear, while line AB and SD are vertical and parallel lines at the either sides of point C.

Hence, Gilligan can conclude that triangles ABC and SDC are similar

How to calculate the distance SD

To do this, we make use of the following equivalent ratio

[tex]SD : 130 = AB : 23[/tex]

Substitute 90 for AB

[tex]SD : 130 =90 : 23[/tex]

Express as fraction

[tex]\frac{SD}{130} =\frac{90}{ 23}[/tex]

Make SD the subject

[tex]SD =\frac{90}{ 23} * 130[/tex]

[tex]SD =509[/tex]

Hence, Gilligan can conclude that the distance of the ship from the shore is 509 ft

Read more about similar triangles at:

https://brainly.com/question/14285697

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