Answer:
the net force on the object is 6 N.
Explanation:
Given;
force applied to the right on the object, [tex]F_r[/tex] = 16 N
force applied to the left of the object, [tex]F_l[/tex] = 16 N
force applied downward on the object, [tex]F_d[/tex] = 6 N
The net horizontal force on the object = [tex]F_r - F_l = 16N -16N = 0[/tex]
The net vertical force on the object = [tex]6 \ N \ downward[/tex]
The net force on the object is calculated as;
[tex]F_{net}^2 = 6^2 + 0\\\\F_{net}^2 = 36\\\\F_{net} = \sqrt{36} \\\\F_{net} = 6 \ N[/tex]
Therefore, the net force on the object is 6 N.
