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a) What mass in grams of H20 is needed to react completely with 40.0 g of
Na2O2?

M(H2O) =18.02g/mol
M(NA2O2)= 78g/mol


2Na2O2 (s)+2h2O(I)—> 4NaOH(aq) + O2 (g)

Respuesta :

sebassandin

Answer:

[tex]m_{H_2O}=9.24gH_2O[/tex]

Explanation:

Hello there!

In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:

[tex]m_{H_2O}=40.0gNa_O_2*\frac{1molNa_O_2}{78gNa_O_2}*\frac{2molH_2O}{2molNa_O_2} *\frac{18.02gH_2O}{1molH_2O} \\\\m_{H_2O}=9.24gH_2O[/tex]

Best regards!