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What is the rate constant of a reaction if rate = 1 x 10^-2 (mol/L)/s, [A] is 2 M,
[B] is 3 M, m = 2, and n= 1?

k= rate
[A] [BT]

A. 1.7 x 10-3
B. 2.5 x 10-3
C. 6.0 x 10-3
D. 8.3 x 10-4

Respuesta :

sebassandin

Answer:

D. 8.3 x 10-4

Explanation:

Hello!

In this case, since the rate law is written solving for the rate constant as:

[tex]k=\frac{r}{[A]^2[B]}[/tex]

Thus, we plug the rate and concentrations to obtain:

[tex]k=\frac{0.01M/s}{(2M)^2(3M)}\\\\k=8.3x10^{-4}M^{-2}s^{-1}[/tex]

Therefore, the answer would be D. 8.3 x 10-4

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