The base of the following pyramid is a square. If the surface area of the pyramid is 896 in^2, what is it's volume? Side base length is 14 and distance to middle is 7.

Respuesta :

Answer: 457.3

Step-by-step explanation:

[tex]V=\frac{lwh}{3}[/tex]

[tex]V=\frac{14*14*7}{3}[/tex]= 457.3

Answer:

V= 1568 in^3

Step-by-step explanation:

B = 14^2 = 196

896 = 14^2 + 2(14) (l)

896 = 196 + 28 (l)

700 = 281 l

25 = l

7^2 + b^2 = 25^2

49 = 625

24

1/3 (196)(24) = 1568