!! HELP ME PLEASE!!
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What is the solution to the equation below?

Answer:
Solve for √3−2x.
√3−2x=4√x
To remove the radical on the left side of the equation, square both sides of the equation.
√3−2x²=(4√x)²
Simplify each side of the equation.
3−2x=16x
Solve for x.
=> x=16
Step-by-step explanation:
Answer:
x = [tex]\frac{1}{6}[/tex]
Step-by-step explanation:
Given
[tex]\frac{\sqrt{3-2x} }{\sqrt{4x} }[/tex] = 2 ( square both sides )
[tex]\frac{3-2x}{4x}[/tex] = 4 ( multiply both sides by 4x )
3 - 2x = 16x ( add 2x to both sides )
3 = 18x ( divide both sides by 18 )
[tex]\frac{3}{18}[/tex] = x , that is
x = [tex]\frac{1}{6}[/tex]