Given:
The slope of the line is m=0.
The line passes through the point P(-9,-3).
To find:
The equation of the line in standard form.
Solution:
Standard form of a line is:
[tex]Ax+By=C[/tex]
The slope intercept form of the line is
[tex]y-y_1=m(x-x_1)[/tex]
Where, m is the slope and [tex](x_1,y_1)[/tex] is the point on the line.
It is given that the slope of the line is 3 and it passes through the point (-9,-3), so the equation of the line is
[tex]y-(-3)=0(x-(-9))[/tex]
[tex]y+3=0[/tex]
[tex]y=-3[/tex]
Therefore, the standard form of the given line is [tex]y=-3[/tex].
