Unit test, Part 2: Measurement of Two-Dimensional Figures Please help!!!

Answer:
Step-by-step explanation:
1. Area of the composite figure = Area of the sector + Area of rectangle
Area of sector = (θ/ 360) x [tex]\pi[/tex][tex]r^{2}[/tex]
From the figure,
θ = 30, and r = 65
Area of sector = [tex]\frac{30}{360}[/tex] x [tex]\frac{22}{7}[/tex] x 65 x 65
= 1 1065.55[tex]m^{2}[/tex]
Area of rectangle = length x width
= 65 x 4
= 260 [tex]m^{2}[/tex]
Area of the composite figure = 1 1065.55 + 260
= 11325.55
Area of the composite figure is 11326 [tex]m^{2}[/tex].
2.
Circle sector is a section of a disk encompassed by two radii and an arc. The area of the composite figure is 29.9194 m².
A circular sector, also known as a circle sector or a disk sector, is a section of a disk encompassed by two radii and an arc, with the minor sector being smaller and the main sector being bigger.
[tex]\text{The area of the sector of the circle }= \pi r^2 \times \dfrac{\theta}{360^o}[/tex]
The area of the composite figure is the sum of the area of the sector of the circle and the area of the rectangle.
The area of the sector of the circle whose angle at the centre of the circle is 30°, while the radius of the circle is the length of the reactangle which is 5.5 cm.
[tex]\text{The area of the sector of the circle }= \pi r^2 \times \dfrac{\theta}{360^o}[/tex]
[tex]= \pi (5.5)^2 \times \dfrac{30}{360^o}\\\\=7.9194\rm\ m^2[/tex]
Thus, the area of the sector of the circle is 7.9194 m².
The area of the reactangle whose length is 5.5 inches while the width is 4 m.
[tex]\rm \text{Area of the rectangle} = Length \times width[/tex]
[tex]= 5.5 \times 4\\\\= 22\rm\ m^2[/tex]
Thus, the area of the rectangle is 22 m².
Now, the total area of the composite figure can be written as,
Area of the composite figure = Area of the sector of circle+Area of rectangle
Area of the composite figure = 7.9194 +22 = 29.9194 m²
Hence, the area of the composite figure is 29.9194 m².
Learn more about Sector of Circle:
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