A bowling ball is attached to a 2.48-meter long cable and hung from the ceiling. The cable is kept taut and the ball is raised to an initial height of 1.61 meters above the classroom floor. It is released from rest and allowed to swing as a pendulum. Determine its speed (in m/s) when it is at a height of 1.23 meters above the floor.

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Explanation:

Speed (in m/s) when it is at a height of 1.23 meters above the floor will be 2.73 m/s

What is Potential energy ?

The energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors is called Potential energy

Potential energy when h1= 1.61m will be : mgh1 = mg(1.61)

Potential energy when h2= 1.23m  will be : mgh2 = mg(1.23)

the change in potential energy will be converted to kinetic energy :

mgh1 - mgh2 = 1/2 m [tex]v^{2}[/tex]

mg(h1-h2) = 1/2 m [tex]v^{2}[/tex]

g(h1 - h2 ) = 1/2 [tex]v^{2}[/tex]

9.8 (1.61 - 1.23 ) = 1/2 [tex]v^{2}[/tex]

[tex]v^{2}[/tex] = 7.448

v= 2.73 m/s

Speed (in m/s) when it is at a height of 1.23 meters above the floor will be 2.73 m/s

learn more about Potential energy:

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