Respuesta :

Answer:

a. 40°

b. 21°

Step-by-step explanation:

a. Reference angle = θ

Opposite = 5

Adjacent = 6

Apply TOA:

[tex] Tan (\theta) = \frac{Opp}{Adj} [/tex]

[tex] Tan (\theta) = \frac{5}{6} [/tex]

[tex] \theta = Tan^{-1}(\frac{5}{6}) [/tex]

[tex] \theta = 40 [/tex] (nearest degree)

b. Reference angle = x

Opposite = 5

Hypotenuse = 14

Apply SOH:

[tex] Sin (x) = \frac{Opp}{Hyp} [/tex]

[tex] Sin (x) = \frac{5}{14} [/tex]

[tex] x = Sin^{-1}(\frac{5}{14}) [/tex]

[tex] x = 21 [/tex] (nearest degree)