Respuesta :
Write the balanced chemical equation
Calculate the moles of
Na2CrO4
Use the molar ratio from the balanced equation to calculate the moles of
Ag2CrO4
Calculate the mass of
Ag2CrO4
mass of Ag2CrO4 produced is 124 g.
The mass of silver chromate are produced when 250. mL of 1.500 M Na₂CrO₄ are added to excess silver nitrate is 62.028g.
How do we calculate mass from moles?
Mass of any susbtance will be calculated by using moles as:
n = W/M, where
W = given mass
M = molar mass
Relation between moles and molarity as:
M = n/V, where
M = molarity
V = volume
Moles of Na₂CrO₄ = (1.5)(0.25) = 0.375 mol
Given balanced chemical reaction is:
2AgNO₃(aq) + Na₂CrO₄(aq) → Ag₂CrO₄(s) + 2NaNO₃(aq)
From the stoichiometry of the reaction it is clear that,
2 moles of Na₂CrO₄ = produces 1 mole of Ag₂CrO₄
0.375 moles of Na₂CrO₄ = produces 1/2×0.375=0.187 mole of Ag₂CrO₄
Mass of 0.187 moles of Ag₂CrO₄ = (0.187mol)(331.7g/mol) = 62.028g
Hence required mass of Ag₂CrO₄ is 62.028g.
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