Answer: 0.99 grams of chlorine gas is produced by the reaction of 3.3g of ammonium perchlorate
Explanation:
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]\text{Number of moles of } NH_4ClO_4=\frac{3.3g}{117.5g/mol}=0.028moles[/tex]
The decomposition of ammonium perchlorate is :
[tex]2NH_4ClO_4\rightarrow Cl_2+N_2+2O_2+4H_2O[/tex]
According to stoichiometry :
2 moles of [tex]NH_4ClO_4[/tex] produce = 1 mole of [tex]Cl_2[/tex]
Thus 0.028 moles of [tex]NH_4ClO_4[/tex] produce=[tex]\frac{1}{2}\times 0.028=0.014moles[/tex] of [tex]Cl_2[/tex]
Mass of [tex]Cl_2=moles\times {\text {Molar mass}}=0.014moles\times 71g/mol=0.99g[/tex]
Thus 0.99 grams of chlorine gas is produced by the reaction of 3.3g of ammonium perchlorate
