savannahschlager5 savannahschlager5
  • 22-03-2021
  • Mathematics
contestada

Solve this for me please i need help with it

Solve this for me please i need help with it class=

Respuesta :

Mekhala
Mekhala Mekhala
  • 22-03-2021

Answer:

sin 60 = 6 sqrt(3) / a

sqrt(3)/2 = 6 sqrt(3) / a

1/2 = 6/a

a =12

sin 30 = b / a

1/2 = b / 12

b=12/2

b=6

Step-by-step explanation:

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