Respuesta :
420 liter of volume is occupied by 300 grams of methane gas at standard temperature and pressure (STP).
How we write the ideal gas equation at STP?
Ideal gas equation of methane gas at STP (standard temperature pressure) can be written as:
PV = nRT, where
P = pressure = 1 atm
V = volume = 420 L (given)
R = universal gas constant = 0.082 L.atm / k.mole
T = absolute temperature = 273 K
n = no. of moles to find?
Putting all these values in the above equation and calculated for the n:
n = (1 × 420) / (0.082 × 273) = 18.76 moles
Now we calculate mass of methane by the definition of moles as:
n = W/M, where
M = molar mass of methane = 16 g/mole
W = to find?
W = 18.76 × 16 = 300.2 grams or 300grams.
Hence, option (c) is correct i.e. 300 grams of methane occupy 420 L volume.
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