The distance dd is 11 mm. What is the perimeter of the figure? Round to the nearest tenth.

Answer:
P = 157.1 mm
Step-by-step explanation:
The perimeter of the figure = Circumference of circle + perimeter of square
We have, d = 11
⇒ Radius = 11 mm
Side of square = 22 cm
So,
[tex]P=2\pi \times 11+4\times 22\\\\P=157.11\ mm\\\\or\\\\P=157.1\ mm[/tex]
So, the perimeter of the figure is equal to 157.1 mm.